Solve and Economic Order Quantity (EOQ) Problem

Case Study: Economic Order Quantity



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Carrying cost, Cc =

$2.00
$10

Annual Demand, D =

36,000

Annual days, months or weeks =

240

Demand rate, d =

150.00

Production rate, p =

300

\[{{Q}^{*}}=\sqrt{\frac{2DS}{H\left( 1-\frac{d}{p} \right)}}=\sqrt{\frac{2\times 36,000\times 10}{2\left( 1-\frac{150}{300} \right)}}=849\]

Qopt =

849

Total Cost, TC =

$848.53

Production run length =

2.83

Number of runs =

42.43

Maximum inventory =

424.26

Cycle Time =

5.66

\[Q*\left( 1-\frac{d}{p} \right)=849\left( 1-\frac{150}{300} \right)=425\]

\[IC=\frac{HQ*}{2}\left( 1-\frac{d}{p} \right)=\frac{2\times 849}{2}\left( 1-\frac{150}{300} \right)=\$424.26\]

\[ROP = d\times L = 150\times 2 = 300\]

\[TC=\frac{DS}{Q}+\frac{HQ}{2}+PD = 2\times \frac{D\times 25}{285}+450.50\times D\]

\[AC=\frac{TC}{D}=\frac{50}{285}+450.50=450.6754\]

\[OC=HC=\frac{HQ}{2}=\frac{0.20\times 450.50\times 285}{2}=\$12,839.25\]

\[OC=\$12,839.25\]